SOLUTION: For many years TV executives used the guideline that 30 percent of the audience were watching each of the traditional big three prime-time networks and 10 percent were watching cab

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 Click here to see ALL problems on Probability-and-statistics Question 245994: For many years TV executives used the guideline that 30 percent of the audience were watching each of the traditional big three prime-time networks and 10 percent were watching cable stations on a weekday night. A random sample of 550 viewers in the Tampa–St. Petersburg, Florida, area last Monday night showed that 175 homes were tuned in to the ABC affiliate, 170 to the CBS affiliate, 165 to the NBC affiliate, and the remainder were viewing a cable station. At the 0.1 significance level, can we conclude that the guideline is still reasonable? Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!For many years TV executives used the guideline that 30 percent of the audience were watching each of the traditional big three prime-time networks and 10 percent were watching cable stations on a weekday night. A random sample of 550 viewers in the Tampa–St. Petersburg, Florida, area last Monday night showed that 175 homes were tuned in to the ABC affiliate, 170 to the CBS affiliate, 165 to the NBC affiliate, and the remainder were viewing a cable station. At the 0.1 significance level, can we conclude that the guideline is still reasonable? -------------------- Network numbers are 175+170+165 = 510 Proportion is 510/550 = 0.9273 Cable numbers are 550-510 = 40 Proportion is 40/550 = 0.0727 ---------------------------------------- It's a Goodness-of-Fit problem. Expected values are 0.30--------------0.10 Observed values are 0.9273-----------0.0727 ---------------------------------------------- Express the comparison in whole numbers: Expected values---3000-----------1000 Observed values---9273------------727 ------------------------------------------- Ho: The proportions are the same H1: At least one of the proportions is different ----------------------- Run a Chi-Sq. Goodness of Fit program on the two rows of data: I got the following: Chi-Sq = 4346.08 p-value is 0 to 4 decimal places ------------------ Conclusion: Reject Ho; These test results support the conclusion that the guidelines should be changed. ===================================================== Cheers, Stan H.