SOLUTION: n! where n=12 and r=4
----------- --
r!(n-r)!
Algebra.Com
Question 235049: n! where n=12 and r=4
--------------
r!(n-r)!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
where n=12 and r=4
--------------
r!(n-r)!
= 4! * 8!
= 24*40320
= 967680
RELATED QUESTIONS
verify
n=n/n-r... (answered by ikleyn)
(r+1)(n+1/r+1)=(n+1)(n/r) (answered by ikleyn)
Show that n! /r!(n-r)! + n!/(r-1)! (n-r+1)! = (n+1)!... (answered by math_helper)
n! / r! =... (answered by edjones)
nCr=nCs;where r=s or... (answered by solver91311)
Prove (n+1)p(r) = (n)p(r) + 4.(n)p(r-1)
(answered by greenestamps,ikleyn)
Whats an example of a geometric series where r = ½ and n = 4? (answered by robertb,ikleyn)
Let n and r be positive integers with n ≥ r. Prove that rCr + (r+1Cr)+...+( nCr) =... (answered by math_helper)
P=r-c/n, solve for... (answered by harpazo)