SOLUTION: When you toss a pair of dice, each containing the digits 1 through 6, what is the probability that the sum of the values face-up on the cubes will not be 3? a) 17/18 b) 1/6 c) 5/6

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: When you toss a pair of dice, each containing the digits 1 through 6, what is the probability that the sum of the values face-up on the cubes will not be 3? a) 17/18 b) 1/6 c) 5/6      Log On

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Question 234955: When you toss a pair of dice, each containing the digits 1 through 6, what is the probability that the sum of the values face-up on the cubes will not be 3?
a) 17/18 b) 1/6 c) 5/6 d) 18/36 e) 3/36.
Answer by Theo(675) About Me  (Show Source):
You can put this solution on YOUR website!
It would be 1 minus the probability that it would be 3.

You have 2 dice.

Total possible number of combinations would be 6*6 = 36

Possible ways you could get a 3 would be:

1 + 2
2 + 1

That's only 2 out of 36.

Possible ways you could not get a 3 would be 34 out of 36.

34 out of 36 is the same as 17 out of 18.

Your answer would be A).