# SOLUTION: A bucket contains 6 orange balls and 8 yellow balls. 5 balls are to be selected at random. What is the probability that, of the 5 balls selected at least one is orange and at leas

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: A bucket contains 6 orange balls and 8 yellow balls. 5 balls are to be selected at random. What is the probability that, of the 5 balls selected at least one is orange and at leas      Log On

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 Question 229911: A bucket contains 6 orange balls and 8 yellow balls. 5 balls are to be selected at random. What is the probability that, of the 5 balls selected at least one is orange and at least one is yellow? What is the probability that, of the 5 balls selected at random, at least two are orange and at least two are yellow?Answer by edjones(7569)   (Show Source): You can put this solution on YOUR website!8/14=fraction of yellow balls=y 6/14=fraction of orange balls=g (y+g)^5=y^5+5y4g+10y^3g^2+10y^2g^3+5yg^4+g^5 a) y^5=(8/14)^5=.0609 no orange g^5=(6/14)^5=.0145 no yellow 1-(.0609+.0145)=.9246 probability of at least one ball of each color. . b) 10y^3g^2+10^2g^3 =10(8/14)^3(6/14)^2+10(8/14)^2(6/14)^3 =.5998 probability at least 2 balls of each color. . Ed