SOLUTION: A car radiator contains 10 liters of 20% anitfreeze solution. How many liters of pure antifreeze are needed to make the solution 50% antifreeze without replacement?

Question 219499: A car radiator contains 10 liters of 20% anitfreeze solution. How many liters of pure antifreeze are needed to make the solution 50% antifreeze without replacement?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
This assumes that the radiator will hold whatever added
antifreeze you try to put in.
In words:
(final liters of antifreeze)/(final liters of total mixture) = 50%
Let = liters of antifreeze to be added

Multiply both sides by

6 liters of antifreeze needs to be added to make mixture 50%
check answer:

OK
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