SOLUTION: if a jar contains 23 red marbles and 4 green marbles, the probability that a marble selectted from the jar at random will be green is? If the above green is not replaced, what i

Question 214683: if a jar contains 23 red marbles and 4 green marbles, the probability that a marble selectted from the jar at random will be green is?
If the above green is not replaced, what is the probability that the next pulled marbles is red?
if you reached into the jar 4 times, what is the probability that you would never choose a green marble (after each pullout you do not replace the chosen marble?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
a)
Total number of marbles = 23 + 4 = 27 marbles

P(Green Marble) = (# of green marbles)/(# of marbles total) = 4/27 = 0.148

So the probability is 4/27 which is about a 14.8% chance

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b)

Since the selected marble from part a) is not replaced, the total number of marbles is now 27-1=26

P(Red Marble) = (# of red marbles)/(# of marbles total) = 23/26 = 0.885

So the probability is 23/27 which is about a 88.5% chance

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c)

To find the probability of NOT choosing green after four selections, you simply calculate the probability of choosing red 4 times in a row (without replacement). This works because there are only two choices in marble selection.

So the basic outline is

P(4 red) = P(red)*P(red with 1 less from total)*P(red with 2 less from total)*P(red with 3 less from total)

I'll let you take it from here. Let me know if you still need help.
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