SOLUTION: Suppose events A and B are independent and P(A)=0.6, P(B)=0.2. Find the probability that at least one of A and B occurs.

Question 214667: Suppose events A and B are independent and P(A)=0.6, P(B)=0.2. Find the probability that at least one of A and B occurs.

Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Suppose events A and B are independent and P(A)=0.6, P(B)=0.2. Find the probability that at least one of A and B occurs.

Step 1. Since the events are independent, we can multiply, their probabilities.

Step 2. Therefore, P(A and B)=P(A)P(B) for independent events. As a result, the probability of A and B is (0.6)*(0.2)=0.12.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
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