SOLUTION: Hello out there does anybody have the solution to this I am racking my brains out Researchers find that the 2004 population of Califonia was 35,893,799, the 2004 population of P

Question 211229: Hello out there does anybody have the solution to this I am racking my brains out
Researchers find that the 2004 population of Califonia was 35,893,799, the 2004 population of Pennsylvania was 12,496,292, and the total US population was 293,655,404. What is the probability that a randomly selected US resident did not live in California? Round to the nearest thousandth of a percent?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
The percent of people in the united states that lived in california in 2004 is 35893799 / 293655404 * 100% = 12.22310181%
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the probability that a randomly selected resident DID live in california in 2004 would be .1222310181. This is the number of people that lived in california divided by the number of people that lived in the US total.
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the probability that a randomly selected resident did NOT live in california in 2004 would be 1 - .1222310181 = .877768982
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this probability is expressed as a ratio.
to convert this ratio into a percent, you need to multiply it by 100%
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the ratio of .877768982 equals 87.7768982%
rounding this percent to the nearest thousandth of a percent makes it equal to:
87.777%
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this represents the % probability that a randomly selected resident will NOT have lived in california in 2004.
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