SOLUTION: HELP! me find the solution to this problem Please. An independent television station airs a movie-of-the-day every Tuesday and Thursday. Their market research shows that their s

Question 211221: HELP! me find the solution to this problem Please.
An independent television station airs a movie-of-the-day every Tuesday and Thursday. Their market research shows that their suspense movies are viewed by an average of 3500 people, their comedies are viewed by 4500 people, and their dramas are viewed by 6000 people. The station buys a package of 100 miview, consisting of 15 suspense movies, 40 comedies, and 45 dramas. The movie will be shown two per week for 50 weeks. Find the expected number of viewers on a fiven movie.
A)4667 B)479 C)140 D)5025 E)1400
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An independent television station airs a movie-of-the-day every Tuesday and Thursday. Their market research shows that their suspense movies are viewed by an average of 3500 people, their comedies are viewed by 4500 people, and their dramas are viewed by 6000 people.
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Let the random variable be # of people who see a movie:
The random number values are 3500, 4500, and 6000
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The station buys a package of 100 movies, consisting of 15 suspense movies, 40 comedies, and 45 dramas.
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List the probabilities of the several random number values.
15/100, 40/100, and 45/100 are the corresponding proabilities
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The movie will be shown two per week for 50 weeks. Find the expected number of viewers on a given movie.
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E(X) = 0.15(3500) + 0.40(4500) + 0.45(6000) = 5025
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Cheers,
Stan H.
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A)4667 B)479 C)140 D)5025 E)1400

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