SOLUTION: Fred’s Widget Company wants to make sure his widgets are within the weight tolerances he advertises on the radio. He says the weight of his widgets is 15 pounds. He samples 49 of
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Question 202431: Fred’s Widget Company wants to make sure his widgets are within the weight tolerances he advertises on the radio. He says the weight of his widgets is 15 pounds. He samples 49 of his widgets and finds the mean weight of the widgets to be 14.5 with a standard deviation of 1.2 pounds. Based on this information, construct the 95 percent confidence interval for the sample.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Fred’s Widget Company wants to make sure his widgets are within the weight tolerances he advertises on the radio. He says the weight of his widgets is 15 pounds. He samples 49 of his widgets and finds the mean weight of the widgets to be 14.5 with a standard deviation of 1.2 pounds. Based on this information, construct the 95 percent confidence interval for the sample.
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x-bar = 14.5
E = 1.96[1.2/sqrt(49) = 1.96*0.1714.. = 0.336
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95% CI: 14.5-0.336 < u < 14.5+0.336
95% CI: 14.164 < u < 14.836
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Cheers,
Stan H.
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