SOLUTION: I missed this one on my quiz yetersday can someone please help me I went wrong so where. ASAP!!!!!!!!!!!!!!!!!
A jar contains 4 yellow marbles, 12 green marbles, and 11 black
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Question 199863: I missed this one on my quiz yetersday can someone please help me I went wrong so where. ASAP!!!!!!!!!!!!!!!!!
A jar contains 4 yellow marbles, 12 green marbles, and 11 black marbles. If one marble is selected at random, what is the probability that it is not yellow?
thank you Terrie
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Take note that there are 4+12+11=27 marbles total.
=1-P\left(\text{Yellow}\right))
=1-\frac{\text{Number of Yellow}}{\text{Number Total}})
=1-\frac{4}{27})
=\frac{27}{27}-\frac{4}{27})
=\frac{27-4}{27})
=\frac{23}{27})
So the probability of NOT choosing a yellow marble is which is in decimal form (which is 85.2%).
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