SOLUTION: Suppose that 2000 people are all playing a game for which the chance of winning is 48%.
a. Assuming everyone plays exactly five games, what is the probability of one person wi
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Question 199711This question is from textbook Using and Understanding Mathematics A Quantitative Reasoning Approach
: Suppose that 2000 people are all playing a game for which the chance of winning is 48%.
a. Assuming everyone plays exactly five games, what is the probability of one person winning five games in a row? On average, how many of the 2000 people could be expected to have a "hot streak" of five games?
b. Assuming everyone plays exactly ten games, what is the probability of one person winning ten games in a row? On average, how many of the 2000 people could be expected to have a "hot streak" of ten games?
This question is from textbook Using and Understanding Mathematics A Quantitative Reasoning Approach
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
a)
.48^5=.0255 chances of winning 5 of 5.
2000*.0255=51 on average will win
.
b)
.48^10=.0006493
2000*.0006493=1 will win on average.
.
Ed
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