SOLUTION: events A AND B are such that P(A)= 0.03 and P(B)= 0.6.if events A and B are independent, find the probability that :
a)neither event A nor B
b) event A occurs given only one eve
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Question 199496: events A AND B are such that P(A)= 0.03 and P(B)= 0.6.if events A and B are independent, find the probability that :
a)neither event A nor B
b) event A occurs given only one event occur. i think it means that if B doesn't exist?
Found 3 solutions by stanbon, nellyothman, Kamaldeenola:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
events A AND B are such that P(A)= 0.03 and P(B)= 0.6.if events A and B are independent, find the probability t0.0hat :
Note: P(A and B) = 0.03*0.60 = 0.018
a)neither event A nor B
neither A nor B = not(A or B)
P(A or B)' = 1 - P(A or B)
= 1 - [P(A) + P(B) - P(A and B)]
= 1 - [0.030 + 0.600 - 0.018]
= 0.388
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b) event A occurs given only one event
Question: What does that mean?
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Cheers,
Stan H.
Answer by nellyothman(2) (Show Source): You can put this solution on YOUR website!
Answer by Kamaldeenola(1) (Show Source): You can put this solution on YOUR website!
Prob neither A nor B = 1 -p(A) +p(B) - p(AnB)
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