You can
put this solution on YOUR website!Biting an unpopped kernel of corn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
---
sample proportion = 86/773 = 0.11
(a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop.
ME = 1.645*sqrt[0.11*0.89/773] = 0.0185
90% CI: 0.11 - 0.0185 < p < 0.11 + 0.0185
---------------------------------------------------------
(b) Check the normality assumption.
I'll leave that to you. Check your textbook.
-----------------------------------------------------------
(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
Not sure what that means.
-------------------------------------------------------------
(d) Why might this sample not be typical?
It is only a sample of convenience sample; not a simple random sample.
================================================================
Cheers,
Stan H.