# SOLUTION: The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4 accidents. This variable is discrete. It is certainly not normaly distr

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 Click here to see ALL problems on Probability-and-statistics Question 193188: The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4 accidents. This variable is discrete. It is certainly not normaly distributed. Let x-bar be the mean number of accidents per week at the intersection during a year.(52 weeks). Question: What is the approximate chance that there are fewer than 130 accidents at the intersection a year? (Restate in terms of x-bar)Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4 accidents. This variable is discrete. It is certainly not normaly distributed. Let x-bar be the mean number of accidents per week at the intersection during a year.(52 weeks). Question: What is the approximate chance that there are fewer than 130 accidents at the intersection a year? (Restate in terms of x-bar) ----------------- 130 per year = 130/52 = 2.5 per week ---- (2.5-2.2)/1.4 = 1.78 So an average of 2.5 accidents perweek is 1.78 standard deviations above the mean of 2.2. ----- The appromate chance the average is less than 2.5 accidents per week is about 96% or 0.9629... ==================================== Comment: Those figures are based on the distribution being normal; but they are suitable as an approximation. ==================================== Cheers, Stan H.