SOLUTION: 4) A number between 1 to 10 is selected at random twice. What is the probability that tha number selected in the second attempt is greater than the number selected previously.?

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Question 192708: 4) A number between 1 to 10 is selected at random twice. What is the probability that tha number selected in the second attempt is greater than the number selected previously.?
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
This may or may not be of some help.
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The "average" number selectd on the 1st draw is 5.5.
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Then the probability the 2nd draw will be greater is (5/10) = 1/2
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Cheers,
Stan H.

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