1 ace AND 4 non-aces.

There are 4 aces, so there are "4 choose 1" 
ways to get the ace.

For each of the 4C1 ways we can pick the ace, 

there are 48 non-aces, so there are "48 choose 4"
ways to get the 4 non-aces.

"AND" usually means to multiply, so the number of 
ways that can be had is 

(4C1)(48C4) = 778320

Edwin