# SOLUTION: 1. There are 4 contestants in a bicycle race. In how many different orders can they cross the finish line? a. 4 b. 10 c. 24 d. 16 2. Clayton has to read 3 books for English Class

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: 1. There are 4 contestants in a bicycle race. In how many different orders can they cross the finish line? a. 4 b. 10 c. 24 d. 16 2. Clayton has to read 3 books for English Class      Log On

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 Question 187060: 1. There are 4 contestants in a bicycle race. In how many different orders can they cross the finish line? a. 4 b. 10 c. 24 d. 16 2. Clayton has to read 3 books for English Class. He can choose from a list of 5 books. HOw many different combinations of 3 books are possible? a. 30 b. 15 c. 10 3.Carly is making cupcakes with nuts.She can choose between 4 flavors of cupcakes,3 colors of frosting,& 2 kinds of nuts. She chooses one flavor, one color & one kind of nut. How many different cupcakes could be made? a.10 b.16 c.4 d.24 4.In a bag of candies there are 13 red candies,13 green candies,13 yellow candies,& 13 blue candies.If you choose 1 candy from the bag,what is the probability the candy will not be blue? a.3/4 b.2/3 c.1/4 d.1/2Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!1. There are 4 contestants in a bicycle race. In how many different orders can they cross the finish line? 4! = 4*3*2*! = 24 a. 4 b. 10 c. 24 d. 16 ----------------------------------------- 2. Clayton has to read 3 books for English Class. He can choose from a list of 5 books. HOw many different combinations of 3 books are possible? 5C3 = 5C2 = (5*4)/(1*2) = 10 a. 30 b. 15 c. 10 ----------------------------------------- 3.Carly is making cupcakes with nuts.She can choose between 4 flavors of cupcakes,3 colors of frosting,& 2 kinds of nuts. She chooses one flavor, one color & one kind of nut. How many different cupcakes could be made? # of cupcakes = 4*3*2 = 24 a.10 b.16 c.4 d.24 ----------------------------------------- 4.In a bag of candies there are 13 red candies,13 green candies,13 yellow candies,& 13 blue candies.If you choose 1 candy from the bag,what is the probability the candy will not be blue? P(not blue) = 26/39 = 2/3 a.3/4 b.2/3 c.1/4 d.1/2 ====================================================== Cheers, Stan H.