You can
put this solution on YOUR website!Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
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(a) Construct a 90% confidence intervel for the proportion of all kernels that would not pop.
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sample proportion: 86/773 = 0.111
E = 1.645*sqrt[0.111*0.999/773) = 0.0186
90%CI: 0.111-0.0186 < p < 0.111+0.0186
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(b) Check the normality assumption.
I'll leave that to you.
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(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
(d) Why might this sample not be typical?
I am not familiar with the "Quick Rule".
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Cheers,
Stan H.