SOLUTION: Suppose that 53% of all adults in a certain community are obese and that 46% suffer from diabetes. If 26% of the adults in this community are both obese and suffering from diabetes

Question 180043: Suppose that 53% of all adults in a certain community are obese and that 46% suffer from diabetes. If 26% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that 53% of all adults in a certain community are obese and that 46% suffer from diabetes. If 26% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)?
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General Formula:
P(A or B) = P(A) + P(B) - P(A and B)
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Your Problem:
P(obese or diabetes) = P(obese)+P(diabetes) - P(obese and diabetes)
= 53% + 40% - 26%
= (93-26)%
= 67/100
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Cheers,
Stan H.
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