SOLUTION: From the ski lodge example, suppose that the probability of breaking your leg is 0.20. (Therefore the probability of not breaking your leg is (1

Question 173396: From the ski lodge example, suppose that the probability of breaking your leg is 0.20. (Therefore the probability of not breaking your leg is (1 – 0.20) = 0.80.) What is the probability that exactly 2 out of 5 people will break their leg? n = 5, x = 2, p = .2, q = .8. What is the probability that less than 2 out of 5 people will break their leg?
Answer by stanbon(48568) (Show Source):
You can put this solution on YOUR website!
From the ski lodge example, suppose that the probability of breaking your leg is 0.20. (Therefore the probability of not breaking your leg is (1 – 0.20) = 0.80.)
What is the probability that exactly 2 out of 5 people will break their leg?
n = 5, x = 2, p = .2, q = .8.
P(x=2) = 5C2(0.2)^2*(0.8)^3 = 10*0.04*0.512 = 0.2048
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What is the probability that less than 2 out of 5 people will break their leg?
P(x= 0 or 1) = 5C0(0.2)^0*(0.8)^5 + 5C1(0.2)^1*(0.8)^4 = 0.73728...
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Cheers,
Stan H.

SOLUTION: From the ski lodge example, suppose that the probability of breaking your leg is 0.20. (Therefore the probability of not breaking your leg is (1 – 0.20) = 0.80.) What is the probab