SOLUTION: Can someone please help..... thank you Al and Rudy each roll ordinary dice once. What's the probability that the number of Ruby's roll is greater than the number of Al's roll?

Question 171735: Can someone please help..... thank you

Al and Rudy each roll ordinary dice once. What's the probability that the number of Ruby's roll is greater than the number of Al's roll?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Al and Rudy each roll ordinary dice once. What's the probability that the number of Ruby's roll is greater than the number of Al's roll?
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Generate a sample space: a 6 by 6 pairing of possible results.
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Count the number of pairs where Ruby's roll is greater than Al's.
Form the probability fraction.
I get 15/36 = 5/12
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Cheers,
Stan H.
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