SOLUTION: trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 80 miles per hour and train B is traveling at 90 miles per hour. Train A passed a s

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trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 80 miles per hour and train B is traveling at 90 miles per hour. Train A passed a station at 1:20am if train B passes the same station at 1:32am At what time will train B catch up with train A?
:
An easy to do this is use the relative speed between the trains which is:
90 - 80 = 10 mph
:
At 1:20 Train B is 12 min behind A
:
*90 = 18 mi
:
At the relative speed of 10 mph, how long will it take to cover 18 mi?
= 1.8 hrs which is 1 hr 48 min
:
1:20 + 1:48 = 3:02 train b catches train a

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When Train B passed the station At 1:32am, how far is Train A since it passed the station earlier at 1:20am? Let's see the distance of Train A:
Remember: -----> working eqn
We get via working eqn,

What will be ?
The difference when Train B and Train A passed the station:
Difference: 12mins---
So,
, Take note of this. This is how far Train A was when Train B passed the station by 1:32am.
.
In finding for , remember too since they're travelling on both directions. Via working eqn,

. Take note highlighted, we need to add 16miles because Train A was already ahead that much, being ahead 12 minutes remember?
Continuing,


--->
= 1hr &36mins
Therefore,
---
This is the time when Train A & Train B will be on the same distance.
In doubt? Go back working eqn,


right?
Thank you,
Jojo