Question 163010: What is the probability of rolling at least an 8 with a single toss of two dice?
Can anyone help me with this, thank you!
Found 2 solutions by consc198, ikleyn:
Answer by consc198(59)   (Show Source):
You can put this solution on YOUR website! In total there are 36 different combination that somebody rolling two dice could get.
The probability of getting at least 8 from the first throw is: 15/35 which is equals to 1/3.
How i got to this solution:
Lets list all combinations:
1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6
2 1 , 2 2 , 2 3 , 2 4 , 2 5 , 2 6
3 1 , 3 2 , 3 3 , 3 4 , 3 5 , 3 6
4 1 , 4 2 , 4 3 , 4 4 , 4 5 , 4 6
5 1 , 5 2 , 5 3 , 5 4 , 5 5 , 5 6
6 1 , 6 2 , 6 3 , 6 4 , 6 5 , 6 6
If you find the total of each combination you will find that there are only 15 combinations that have a total of 8 or more which is how i got to the answer.
Answer by ikleyn(53937)  (Show Source):
You can put this solution on YOUR website! .
What is the probability of rolling at least an 8 with a single toss of two dice?
Can anyone help me with this, thank you!
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The answer by @consc198, " 15/35, which is equal to 1/3 ", is two times wrong.
The total number of different outcomes is 6 x 6 = 36 (the space of events).
Of them, the number of outcomes with the sum " at least 8 " is 15: they are listed below
(6,6)
(5,6) (6,5)
(4,6) (5,5) (6,4)
(3,6) (4,5) (5,4) (6,3)
(2,6) (3,5) (4,4) (5,3) (6,2)
Therefore, the probability of rolling the sum at least 8 is  =  . ANSWER
Solved correctly.
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