SOLUTION: can someone please help me with this problem: How many 3-digit numbers can be formed using the digits 0,1,2,3,4,5,6 if repetition of digits is not allowed? a. 210 b. 5 c. 6

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You have 7 digits to choose from. After using one of them, you will only have 6 and after using another, you will only have 5. So this means that the number of possible combinations are


7*6*5 = 42*5 = 210

So there are 210 ways that a three digit number can be formed using the digits 0,1,2,3,4,5,6 and repetition is not allowed