SOLUTION: If a couple plans to have eight children, find the probability that they are all of the same gender. Thanks a lot.

Question 15121: If a couple plans to have eight children, find the probability that they are all of the same gender.
Thanks a lot.
Found 2 solutions by rapaljer, biplavmehta:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
The probability of having a boy is 1/2, and the probability of having a girl is also 1/2.

To find the probability of having successive children of a particular gender, assuming that the birth of each child is independent of every other child is the product of the probabilities. Suppose the first child born determines the gender, boy or girl, of all the other children. Therefore, if there are 8 children, the probability that the succeeding SEVEN children will match the gender of the first child will be

R^2 at SCC
Answer by biplavmehta(3) (Show Source): You can put this solution on YOUR website!
chances of having boy or a girl is 1/2.
therefore having all of same gender is 1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2= 1/256.
RELATED QUESTIONS
If a couple plans to have eight children, find the probability that they are all of the... (answered by stanbon)
A couple decided to have 5 children. (a) What is the probability that they will have... (answered by josmiceli)
A couple plans to have three children. Find the probability that they will have:a) All... (answered by stanbon)
if a couple plans to have 6 children, what is the probability that they will have at... (answered by Fombitz)
If a couple plans to have ten children, how many gender sequences are possible? (answered by stanbon)
If a couple plans to have 10 children how many gender sequences are... (answered by user_dude2008)
If a couple plans to have seven children, how many gender sequences are... (answered by Alan3354)
Gender of Children: Constructing Sample Space. This section included a table summarizing... (answered by stanbon)
A couple is planning to have 4 children. Assume boys and girls are equally likely and... (answered by mathmate)