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put this solution on YOUR website!Remember, the combination formula is:
So this means that
!8!})
and
So

becomes:
!8!}=\frac{1}{\left(n-7\right)!7!})
Divide both sides by

. Notice how the

terms cancel out.
!7!=\left(n-8\right)!8!)
Cross multiply
!(7)(6)(5)(4)(3)(2)(1)=\left(n-8\right)!(8)(7)(6)(5)(4)(3)(2)(1))
Expand

to get

. Expand

to get
Notice how the terms

cancel out.
!=\left(n-8\right)!(8))
Simplify.
!=8\left(n-8\right)!)
Rearrange the terms.
!}{8\left(n-8\right)!}=1)
Divide both sides by
\left(n-8\right)\left(n-9\right)\left(n-10\right)\cdots(3)(2)(1)}{\left(n-8\right)\left(n-9\right)\left(n-10\right)\cdots(3)(2)(1)}=1)
Expand the factorials

Cancel out the common terms.

Simplify

Multiply both sides by 8.

Add

to both sides.

Combine like terms on the right side.
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Answer:
So the answer is