In a shop there are 20 customers, 18 of whom will make a purchase. If three customers are selected, one at a time, at random, what is the probability that all will make a purchase? Is it 0.7717, 0.7605, 0.8524, or 0.8808.
Please help
It's not any of those. It's 0.7158
P(1st chosen will purchase
AND
2nd chosen will purchase
AND
3rd chosen will purchase)
=
P(1st chosen will purchase)
TIMES
P(2nd chosen will purchase, given that the 1st chosen will purchase)
TIMES
P(3rd chosen will purchase, given that the 1st and 2nd chosen will purchase)
=
or rounded to ten-thousandths,
.
You can also do it using combinations:
=
Stanbon's solution is incorrect because
the choices are not independent. Binomial
probabilities are ONLY for independent choices.
The choices are not independent because the
probability of selecting the second one as a
purchaser CHANGES after selecting the first one.
Also the probability of selecting the third one
as a purchaser CHANGES after selecting the
first two.
Edwin