Question 144489: Scrap Per Thousand Units
Plant A Plant B Plant C
11.4 11.1 10.2
12.5 14.1 9.5
10.1 16.8 9.0
13.8 13.2 13.3
13.7 14.6 5.9
1.State the null and alternate hypothesis. 2.What is the decision rule? 3.Compute SSA,SSE,and SST using Excel. 4.Complete a one-factor ANOVA table. 5.State the decision rule regardingthe null hypothesis. 6.Does the data prove significant difference in mean scrap rates?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Scrap Per Thousand Units
Plant A Plant B Plant C
11.4 11.1 10.2
12.5 14.1 9.5
10.1 16.8 9.0
13.8 13.2 13.3
13.7 14.6 5.9
1.State the null and alternate hypothesis.
Ho: u1= u2= u3
Ha: atleast one of the means is not equal
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2.What is the decision rule?
Let alpha = 5%
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3.Compute SSA,SSE,and SST using Excel.
I'll let you run EXCEL on the data
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4.Complete a one-factor ANOVA table.
Using a TI caluculator I get:
F = 5.309156...
p-value = 0.02230..
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5.State the decision rule regardingthe null hypothesis.
Since the p-value is less than 5%, reject Ho.
At least one of the means if different.
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6.Does the data prove significant difference in mean scrap rates?
Yes
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Cheers,
Stan H.
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