# SOLUTION: Stan, will you please explain how you got the answers below. Thank you very much The ANOVA table is somewhat standardized among various software packages. Formulate the null an

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Stan, will you please explain how you got the answers below. Thank you very much The ANOVA table is somewhat standardized among various software packages. Formulate the null an      Log On

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 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Question 138706: Stan, will you please explain how you got the answers below. Thank you very much The ANOVA table is somewhat standardized among various software packages. Formulate the null and alternate hypothesis and decide whether or not to reject it from the ANOVA table data provided below. ------------------------------------------ One factor ANOVA Mean n Std. Dev 7.1 5.7 10 1.34 Group 1 7.1 6.6 10 0.97 Group 2 7.1 9.0 10 1.15 Group 3 7.1 30 1.81 Total ANOVA table Source.. SS df MS F p-value Treatment 58.20 2 29.100 21.53 ...2.57E-06 Error ........36.50 27 1.352 Total ........94.70 29 Post hoc analysis Tukey simultaneous comparison t-values (d.f. = 27) Group 1 Group 2 Group 3 5.7 6.6 9.0 Group 1 ........5.7 Group 2 ........6.6 1.73 Group 3 ........9.0 6.35 4.62 critical values for experimentwise error rate: 0.05 2.49 0.01 3.18 p-values for pairwise t-tests Group 1 Group 2 Group 3 5.7 6.6 9.0 Group 1 ........5.7 Group 2 ........6.6 .0949 Group 3 ........9.0 8.54E-07 .0001 --------------------------------------------------- Ho: The means of the three Groups were all equal Ha: At least one of the means was different. Since p-value = 0.00000257, Reject Ho. Conclusion: At least one of the mean values is different. =============================== Cheers, Stan H. Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!It's not obvious what Ho is. What do you think it is? cheers, Stan H.