You can
put this solution on YOUR website!Daily output of Marathon's refinery is normally distributed with a mean of 232000 barrels of crude oil per day with a standard deviation of 7000 barrels.
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What is the probability of producting at least 232000 barrels?
P(0 < z) = 0.50
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Between 232000 and 239000 barrels?
P (232000 < x < 239000) = P(0 < z < [(239000-233200/7000]) = P(0
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I have a feeling that you have posted the wrong standard deviation. Are you
sure it's not 70,000?
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Cheers,
Stan H.
Less than 239000 barrels?
Less than 245000 barrels?
More than 225000 barrels?
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