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put this solution on YOUR website!A researcher collected sample data for 11women ages 18 to 24 The sample had a mean serum cholesterol level (measured in mg/100 mL) of 189.9 with a standard deviation of 8.8. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 95 confidence interval for the mean serum cholesterol level of all women in this age group.
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Formula:
x-bar = 189.9
E = t= 1.812 = 4.8078
95% CI: 189.9-4.8078 < u < 189.9+4.8078
95% CI: 185.09 < u < 194.71
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Cheers,
Stan H.
Then complete the table below.
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.