You can
put this solution on YOUR website!I order to win a game. Nelson must throw a 7 in a single toss of a pair of dice. Larry bets that Nelson will; Benny bets that Nelson won't. What are the odds for and against this event? Do the odds favor Larry or Benny?
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P(7) = 1/6 ; P(not 7) = 5/6
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Odds for the event = (1/6)/(5/6) = 1:5
Odds against the even = (5/6)/(1/6) = 5:1
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The odds favor Benny because the odds against Nelson throwing a 7
are 5:1
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Cheers,
Stan H.