# SOLUTION: In a survey of 1002 people, 701 said that they voted in a recent presidental election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actua

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 Question 126658This question is from textbook Elementary Statistics : In a survey of 1002 people, 701 said that they voted in a recent presidental election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote. a. Find a 99% confidence interval estimate of the proportion of people who say that they voted. b. Are the results consistent with the actual voter turnout of 61% why or why not?This question is from textbook Elementary Statistics Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!In a survey of 1002 people, 701 said that they voted in a recent presidental election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote. ------------------- a. Find a 99% confidence interval estimate of the proportion of people who say that they voted. p-hat = x/n = 701/1002 = 0.6996 E=z*sqrt[(p-hat)(q-hat)/n] = 2.575*sqrt[(0.6996)(0.3004)/1002] = 0.037292 --------- 99% C.I.: (0.6996-0.03729,0.6996+0.0729) = (0.662308,0.736892) b. Are the results consistent with the actual voter turnout of 61% why or why not? No, because 61% does not fall in the confidence interval range of values for p. ============================= Cheers, Stan H.