SOLUTION: find three consecutive integers such that 5 times the sum of the first and third is 14 greater than 8 times the second.

Question 122332: find three consecutive integers such that 5 times the sum of the first and third is 14 greater than 8 times the second.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!


Let the first of three consecutive integers be .

Then the second is  and the third is .


The sum of the first and third is  or .
5 times that is 

This quantity is (meaning equals) 14 greater than 8 times the second.
8 times the second is , and 14 more than that is
, so we can write:





Add  to both sides




Add  to both sides




Multiply by 




Therefore the first number is , the second is  and the third is .


Check the answer


6 plus 8 = 14.   5 times 14 = 70
8 times 7 = 56.  56 plus 14 = 70

Answer checks

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