SOLUTION: There were 10 more reds than 8 times the number of blues. Also the number of red was 5 less than 11 times the number of blues. How many of each were there?

Question 122252: There were 10 more reds than 8 times the number of blues. Also the number of red was 5 less than 11 times the number of blues. How many of each were there?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Write an equation for each statemen:
:
"There were 10 more reds than 8 times the number of blues."
R = 8B + 10
:
"Also the number of red was 5 less than 11 times the number of blues."
R = 11B -5
:
How many of each were there?
Substitute (8B+10) for R in the above equation
8B + 10 = 11B - 5
10 + 5 = 11B - 8B
15 = 3B
B =
B = 5 Blues
:
Find R
R = 8B + 10
R = 8(5) + 10
R = 50
:
Check solutions in R = 11B - 5
50 = 11(5) - 5; confirms our solutions
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