SOLUTION: You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find ​P(Upper A and Upper A ). Question c

Algebra.Com
Question 1207296: You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find ​P(Upper A and Upper A ).
Question content area bottom
Part 1
​P(Upper Aand Upper A)equals=

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's.
You replace the first tile in the bag and then choose again. Find ​P(Upper A and Upper A ).
Question content area bottom
Part 1
​P(Upper A and Upper A) equals =
~~~~~~~~~~~~~~~~~~

Total tiles in the bag is 3+2+4 = 9.


P(A) =  =  = .


Since choosing is with replacement, the conditions to choose the second tile are the same 
as for the first tile.


THEREFORE,  P(A and A) = P(A)*P(A) =  = .    ANSWER

Solved.



RELATED QUESTIONS

You choose a tile at random from a bag containing 2 A's, 3 B's, and 4 C's. You replace... (answered by ikleyn)
You choose a tile at random from a bag containing 2A's, 3B's, and 4C's. You replace the... (answered by rothauserc)
In a word game, you choose a tile from a bag, replace it, and then choose another. If... (answered by richwmiller,edjones)
A bag has 6 number tiles numbered one through six. You draw a number tile, replace the... (answered by checkley77)
A bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. What is the... (answered by stanbon)
a bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. A tile is... (answered by jim_thompson5910)
A bag contains 2 A's, 3 B's, and 4 C's. You choose a letter and replace it. Then you... (answered by sudhanshu_kmr)
You have a bag of 5 red balls, 3 yellow, 4 blue and 3 green. You draw a tile, replace... (answered by Alan3354)