A boy can't go in the middle, for that would leave an odd number of boys, 3, to be divided to go on both sides of him, which would not be symmetrical. So 1 girl must go in the middle with 2 boys and 1 girl on each side of her. To be symmetrical sex-wise, each arrangement must be in one of these 3 forms sex-wise: GBBGBBG, BGBGBGB, or BBGGGBB In each of those 3 forms, the girls can be arranged 3! ways, and the boys 4! ways: So the answer is (3)(3!)(4!) = 432 ways. Edwin