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An urn contains 8 red chips, 10 green chips, and 2 white chips.
A chip is drawn and replaced, and then a second chip drawn.
What is the probability of
(a) a white chip on the first draw?
(b) a white chip on the first draw and a red on the second?
(c) two green chips being drawn?
(d) a red chip on the second given that a white chip was drawn on the first?
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The total number of balls is 8 + 10 + 2 = 20.
Since this experiment is with replacement, the situation after first draw and replacement
is the same as the starting situation.
(a) P = = = 0.1 = 10%. ANSWER
(b) P = = = = = 0.04 = 4%. ANSWER
(c) P = = = = = 0.25 = 25%. ANSWER
(d) P = = = = 0.4 = 40%, independently of the first draw. ANSWER
Solved.
All formulas are SELF-EXPLANATORY.
Your job is to understand the logic of the solution looking at the formulas.