.
I will solve the second problem, ONLY, which is 4.6, 4.6.1, 4.6.2.
4.6.1. P = = . ANSWER
In wording form: in all, 8 outcomes are possible:
(1) H H H
(2) H H T
(3) H T H
(4) H T T
(5) T H H
(6) T H T
(7) T T H
(8) T T T
Of them, only one outcome is favorable: it is (H H H).
It gives the probability .
4.6.2. In the list of possible outcomes above,
find all outcomes with two H and one T.
There are three such outcomes. They are (2), (3) and (5).
Therefore, the probability in this problem is P = . ANSWER
Solved.
///////////////////
Do not pack more than ONE problem per post.