SOLUTION: Please help me solve this problem!Thanks! Given a binomial distribution in which the probability of success is 0.53 and the number of trials is 14, what is the probability for e

Question 1203227: Please help me solve this problem!Thanks!
Given a binomial distribution in which the probability of success is 0.53 and the number of trials is 14, what is the probability for each of the following:
(Round your answers to 3 decimal places.)
Getting exactly 12 successes?

Getting more than 12 successes?

Getting less than or equal to 12 successes?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
p(x) = p^x * q^(n-x)*c(n,x)

n = 14
x = 0 to 14
p = .53
q = 1 minus p = .47

probability of getting exactly 12 successes is p(12) = .53^12 * .47^(14-12) * c(14,12) = 0.009875237.

probability of getting more than 12 successes is equal to p(13) + p(14) = 0.001713216 + 0.000137995 = .001851211.

probability of getting less than or equal to 12 successes is 1 minus the probability of getting more than 12 successes is equal to 1 minus p(13) minus p(14) = 1 minus 0.001713216 minus 0.000137995 = .998148789.

here's what it looks like in excel.

total probbility is equal to 1, as it should.

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