SOLUTION: In a recent poll, 380 people were asked if the like dogs, and 68% said they did. Find the margin of error for this poll, at the 99% confidence level. Give answer to four decimal p
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Question 1203043: In a recent poll, 380 people were asked if the like dogs, and 68% said they did. Find the margin of error for this poll, at the 99% confidence level. Give answer to four decimal places if possible.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
n = sample size = 380
p = percent of people who said they liked dogs = 68% = .68.
q = percent of people who did not say they liked dogs = 32% = .32.
s = standard error = sqrt(p * q / n) = .0012275688.
critical z-score at 99% two tail confidence interval = plus or minus 2.5758.
margin of error = (x-m).
when z = 2.5758, z-score formula becomes 2.5758 = (x-m) / .0012275688.
solve for (x-m) to get (x-m) = .0031619718.
with the mean of .68, that would lead to a 99% confidence interval of from .67684 to .68316.
here's what it looks like on a normal distribution calculator.
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