SOLUTION: We know both the mean and the standard deviation for the population of Total Behavior Problems scores (µ = 50 and σ = 10). Assume that we have a sample of fifteen children who ha

Question 1202093: We know both the mean and the standard deviation for the population of Total Behavior Problems scores (µ = 50 and σ = 10). Assume that we have a sample of fifteen children who had spent considerable time in a hospital for serious medical reasons, and further suppose that they had a mean score on the Child Behavior Checklist (CBCL) of 56.0. Test the null hypothesis that these fifteen children are a random sample from a population of normal children (i.e., normal with respect to their general level of behavior problems). Use α = 0.05. Set up 95% CI.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i used the normal distribution calculator at https://www.statskingdom.com/110MeanNormal1.html

the results are shown below.

first the inputs.

next the output.

the results are significant, indicating that there is a real difference in the mean of the sample versus the population and that it is not due to random variations in the sample means.

this means that these children are probably not from the norml population.

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