P(blue on cover) = (5+1)/16 = 6/16



Since the book will be replaced, the denominator will remain at 16 and the outcome of the 2nd selection can be computed independently:

P(white on cover) = (3+1)/16 = 4/16



The problem asks for both of these independent events occurring, so we must multiply the above two computed probabilities to get the overall probability:



  P(B on cover then W on cover, on two independent selections) = (6/16)(4/16) = 24/256 = 3/32 or about 0.09375

 

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