Last digit (ones digit) must be one of the three possibilities 2, 4, 6. 1st digit can be any of remaining 5 digits; 2nd digit can be any of remaining 4 digits; 3rd digit can be any of remaining 3 digits; In total, there are 3*5*4*3 = 180 such 4-digit numbers. ANSWER
Without restriction on parity, 6*5*4*3 = 360 numbers are possible. Of them, exactly half, 360/2 = 180, are even numbers.