SOLUTION: Eleven points are equally spaced on a circle.
How many ways can 5 of these points be chose as the vertices of a pentagon?
Algebra.Com
Question 1201831: Eleven points are equally spaced on a circle.
How many ways can 5 of these points be chose as the vertices of a pentagon?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Since the 11 points are on a circle, no three of them can be collinear, so there is no restriction on which of the 5 points can be chosen. So
ANSWER: C(11,5) = 462
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