SOLUTION: An urn contains 8 orange balls and 4 green balls. If Vince chooses 5 balls at random from the urn, what is the probability that he will select 3 orange balls and 3 green balls? Rou

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Question 1201698: An urn contains 8 orange balls and 4 green balls. If Vince chooses 5 balls at random from the urn, what is the probability that he will select 3 orange balls and 3 green balls? Round your answer to 3 decimal places.
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


ANSWER: 0

He can't get 3 orange balls and 3 green balls if he chooses only 5 balls from the bag....

To set up the problem for solving, I will assume that he picked 6 balls from the bag instead of 5.

The possible outcomes are all the ways he can choose 6 of the 12 balls.

The good outcomes are the ways he can choose 3 of the 8 orange balls and 3 green balls.
                                       C(8,3) * C(4,3)
  P(3 of 8 orange AND 3 of 4 green) = -----------------
                                           C(12,6)

Use a calculator; and round the answer as directed....


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