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A survey of athletes at a high school is conducted, and the following facts are discovered:
45% of the athletes are football players, 28% are basketball players,
and 15% of the athletes play both football and basketball.
An athlete is chosen at random from the high school: what is the probability that the athlete
is either a football player or a basketball player?
Probability =
% (Please enter your answer as a percent)
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This question "Either . . . Or" means
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| " . . . is a football player or is a basketball player, |
| but not a football player and a basketball player at the same time?" |
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The answer is P = (45%-15%) + (28%-15%) = 30% + 13% = 43%.
Solved, with complete explanations.