SOLUTION: A distribution of values is normal with a mean of 40 and a standard deviation of 98. Find P39, which is the score separating the bottom 39% from the top 61%. P39 = Enter

Question 1200603: A distribution of values is normal with a mean of 40 and a standard deviation of 98.
Find P39, which is the score separating the bottom 39% from the top 61%.
P39 =

Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.the same aptitude, but use different scales.
Answer by GingerAle(43) (Show Source): You can put this solution on YOUR website!
**1. Find the z-score corresponding to P39:**
* P39 means the 39th percentile.
* We need to find the z-score that corresponds to the area below it in the standard normal distribution table.
* Using a standard normal distribution table or a calculator, we find that the z-score corresponding to the 39th percentile is approximately **-0.279**.
**2. Calculate P39:**
* Use the formula:
* P39 = μ + (z-score * σ)
* where μ is the mean and σ is the standard deviation.
* P39 = 40 + (-0.279 * 98)
* P39 = 40 - 27.302
* P39 ≈ 12.7
**Therefore, P39 is approximately 12.7.**

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