SOLUTION: Suppose X has a Binomial distribution with n trials, and a probability of success p. The moment generating function for X has been shown to be
MX (t) = (pe^t + (1 − p))^n.
Usin
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Question 1200317: Suppose X has a Binomial distribution with n trials, and a probability of success p. The moment generating function for X has been shown to be
MX (t) = (pe^t + (1 − p))^n.
Using this result, find the distribution of the random variable Y for the following moment generating function.
MY (t) = (2+e^t)^5/3^5
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Hint:
I'll let the student finish up.
Side note: You should use parenthesis to indicate (2+e^t)^5 is over top 3^5
So you should write ((2+e^t)^5)/(3^5)
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